This is an investigation of sequences formed by writing down
the sum of the squares of the digits of each number to get the
next number in the sequence. A number is called happy if it
starts a sequence that goes to a number which is repeated over
and over again (e.g. 1, 1, 1, 1, $\ldots$) and this is called a
fixed point. Other numbers lead to cyclic patterns which repeat
over and over again. For example this sequence leads to a
repeating 8-cycle:
25, 29, 85, 89, 145, 42, 20, 4, 16, 37, 58, 89, $\ldots$
Rachel Walker from the Mount School, York explained that in
base ten, 122 is a sad number because it has an 8-cycle like 25
and this is her solution:
122, 9, 81, 65, 37, 58, 89, 145, 42, 20, 4, 16, 37, 58........
You can find a lot of 'happy numbers' such as: 310, 70, 86,
130, 7, 5555, 1212, 13, 1000 and other numbers which are
variations of these, e.g. swapping the numbers the other way
around (13, 31) and adding zeros onto the end of numbers (31,
310). Also you get numbers that add up to other happy numbers
e.g. 5555 - four fives squared = 100.
The following sequences are the patterns of fixed points and
cycles in base eight that I have found. These are fixed points
so they are happy numbers and any numbers which start sequences
ending like this are happy numbers.
64, 64, 62, 64, 64, $\ldots$
24, 24, 24, 24, 24, $\ldots$
1, 1, 1, 1, ,1, $\ldots$
These are 2-cycles:
32, 15, 32, 15, 32, 15, $\ldots$
20, 4, 20, 4, 20, 4, $\ldots$
This is a 3-cycle:
31, 12, 5, 31, 12, 5, 31, 12, 5, $\ldots$
Pen Areecharoenlert, also from The Mount School, York found
some more happy numbers and cycles in base eight. Pen says
"There does not appear to be any pattern in which ones are
happy, but it looks as though there are 3 fixed points: 1, 24
and 64." This is Pen's list.
1, 1, 1, $\ldots$ so 1 is happy.
2, 4, 20, 4, 20, $\ldots$ so 2 is sad. (2-cycle)
3, 11, 2, 4, 20, $\ldots$ so 3 is sad. (2-cycle)
4 is sad. (2-cycle)
5, 31, 12, 5, $\ldots$ so 5 is sad. (3-cycle)
6, 44, 40, 20, 4, 20, $\ldots$ so 6 is sad. (2-cycle)
7, 61, 45, 51, 32, 15, 32, $\ldots$ so 7 is sad. (2-cycle)
10, 1, 1, 1, 1$\ldots$ so 10 is happy.
11, 2, 4, 20, 4, $\ldots$ so 11 is sad. (2-cycle)
12, 5, 31, 12, $\ldots$ so 12 is sad. (3-cycle)
13, 12, $\ldots$ so 13 is sad. (3-cycle)
14, 21, 5, $\ldots$ so 14 is sad. (3-cycle)
5, 32, 15,$\ldots$ so 15 is sad. (2-cycle)
16, 45, 51, 32, $\ldots$ so 16 is sad. (2-cycle)
17, 62, 50, 31,$\ldots$ so 17 is sad. (3-cycle)
20, 4, 20, 4, $\ldots$ so 20 is sad. (2-cycle)
21, 5, $\ldots$ so 21 is sad. (3-cycle)
22, 10, 1, 1,$\ldots$ so 22 is happy.
23, 15, $\ldots$ so 23 is sad. (2-cycle)
24, 24, 24, 24, so 24 is happy.
25, 35,, 42, 24, 24,$\ldots$ so 25 is happy.
26, 50, 31,$\ldots$ so 26 is sad. (3-cycle)
27, 65, 75, 112, 6, 44, 40, 20,$\ldots$ so 27 is sad. (2-cycle)
30 , 11, 2, 4, 20, $\ldots$ so 30 is sad. (2-cycle)
31, 12, $\ldots$ so 31 is sad. (3-cycle)
32, 15, $\ldots$ so 32 is sad. (2-cycle)
33, 22, 10, 1, $\ldots$ so 33 is happy.
34, 31, 12, $\ldots$ so 34 is sad. (3-cycle)
35, 42, 24, 24, $\ldots$ so 35 is happy.
36, 55, 62, 50, 31, $\ldots$ so 36 is sad. (3-cycle)
37, 72, 65, 75, 112 so 37 is sad. (2-cycle)
40 > 20 > 4 > 20 so 40 is sad. . (2-cycle)
41, 21, 5, 31, 12, 5, $\ldots$ so 41 is sad. (3-cycle)
42, 24, 24,$\ldots$ so 42 is happy.
43, 31, $\ldots$ so 43 is sad. (3-cycle)
44, 40, 20, 4, 20,$\ldots$ so 44 is sad. (2-cycle)
45, 51, 32, $\ldots$ so 45 is sad. (2-cycle)
46, 64, 64, 64, $\ldots$ so 46 is happy.
47, 101, 2, 4, 20, $\ldots$ so 47 is sad. (2-cycle)
Claire Kruithof, Madras College, St Andrews proved that 24 and
64 are the only 2 digit fixed points in base 8. This is
Claire's proof:
"We wanted to see if there would be any more fixed points so we
used algebra. The number following $ab$ is $a^2 + b^2$ where
$a$ and $b$ are between 0 and 7. For a fixed point we have:
\[a^2 + b^2 = 8a + b\] \[b^2 - b = 8a - a^2\] \[b(b - 1) = a (8
- a)\]
Searching for possibilities
| B |
a |
| 1 x 0 = 0 |
7 x 1 = 7 |
| 2 x 1 = 2 |
6 x 2 = 12 |
| 3 x 2 = 6 |
5 x 3 = 15 |
| 4 x 3 = 12 |
4 x 4 = 16 |
| 5 x 4 = 20 |
|
| 6 x 5 = 30 |
|
| 7 x 6 = 42 |
|
The only possibilities are $a = 2, \ b = 4$ and $a = 6, \ b = 4$.
With more digits the sums of squares are never bigger than some
multiple of $7^2$. It can be proved that sequences cannot go on
for ever without repeating patterns and so all sequences go into
cycles or go to a fixed point. Moreover it can be proved that
there are no fixed points with 3 or more digits.