We had ideas from the Inter School in Zurich, Switerland,
  Moorfield Junior School, Higher Bebington Junior School on the
  Wirral, Yarm Primary School, Cummersdale School in Carlisle as
  well as from students in Etobicoke, Ontario, Canada. There was
  quite a range of answers for this problem, from four ways to 740
  ways to put the ten coins into the plum puddings! Here's what Tom
  did. He was very systematic, so we know that he has counted all
  the possibilities but hasn't counted any twice.<br />
  <br />
  I know that each pudding must have at least two coins. <br />
  <br />
  No pudding can have more than six coins, or there wouldn't be
  enough left for the other two.<br />
  <br />
  If one pudding has six coins, then the other two must each have
  two coins, and that uses all ten. <br />
  <br />
  If one pudding has five coins, then one of the others must have
  three and the other two.<br />
  <br />
  If one pudding has four coins, then either another could have
  four and the third just two, or the remaining two could have
  three each. <br />
  <br />
  If no pudding has four or more coins, then we wouldn't have used
  all the coins. So these four possibilities are the only
  ones.<br />