Well Amy and her dominoes had more than one problem this month! As Edward Quentrill from Tattingstone Primary School wrote, "There are 28 dominoes in a complete set. All of the spots add up to 168. 104 from 168 spots = 64 spots. It is not possible to have four dominoes that make 64 spots. So, I think Amy must have two sets mixed up."

That is a very sound explanation Edward. Good reasoning. Many people though they could solve that problem, but Edward was correct. If you checked in to the site later on in the month, you might have been observant enough to see a change in the problem.

You were asked, if there were 126 spots on the dominoes Amy had, what could the four missing dominoes be? Alice Wilson, Kim Lancaster, as well as Rebecca Burnham and Jamie Pollard from Harden Primary School, each figured out the missing pieces had to show: 6and 6, 5 and 6, 4 and 6 and also 5 and 5. Was there any other possible combination? How about if there was one spot less missing - so that there were 126 spots. What might the possibilities be? Would there be more, fewer or could the problem not be solved?

For those of you who like some follow up thinking, let me ask you this: If Amy had not 104, but 140 spots could you have found a solution? Is there just one possible answer or more? What was the fewest number of spots that could have been on the dominoes if 4 of them were missing? What could have been the greatest number of spots on a set that was missing four pieces? Better stop, before you get spots in front of your eyes!