We had many correct answers to this problem, including some well argued solutions from Thomas Wong (Reed High School, Sparks, Nevada, USA) and Stelios Serghiou (G.C.School of Careers).

Peter Simpson from Castell Alun School argued as follows:

The number must be odd because the holiday makers split into two group, with the car group one less than the walkers.

If N was 7 (or greater) the time delays would be greater than 59 minutes, the time for the car to travel to B (the walkers arrive in 60 minutes - N miles in an hour, the car arrives 1 minute earlier).

If N was 3 the distance would be 22km, but this would mean the holiday makers would split into 2 walkers and 1 car traveller, and as the problem states "they" for the car travellers the number of people in the car must be greater than 1.

Therefore N is 5, and the distance by road is 20km.

Momtchil Iliev from Drayton Manor School argued in a very similar way and added an explanation for how he calculated the distance by road:

Calculating Distance of road travelled by car

Time taken driving = 59 - (5)² - 2(5)
= 59 - 25 - 10 = 24 minutes = 0.4 hours

Speed of travelling by car = 10N = 10(5) = 50 km/h

Distance of road = Speed of car x time taken travelling
= 50 x 0.4 = 20km

Harry also sent in his work on this problem:

Well done to you all.