We know that p=t and q=1-t, so p » 0.760 and q » 0.240.

The height of the equilateral triangle is 1+s=tÖ3 so s » 0.316.

We can use Pythagoras' Theorem to find m: m²=s²+(1-t)² » 0.156, so m » 0.397.

Now we can work out q:

tanq =

1-t s

» 0.760

, so q » 37.2^°.

From the sine rule, we have

u sin30°

=

1 sin(150-q)

, so

u=

1 2sin(150-q)

» 0.542

.

Also from the sine rule,

n=

sinq sin(150-q)

» 0.656

.

By looking at the longest line across the square, we have

1 m+u+v

=cosq

, so

v=

1 cosq

-m-u » 0.317

.

By looking at the rectangle and considering the diagonal, we see that (r+n)²=(1+s)²+t², so

r=

________ Ö(1+s)2+t2

-n » 0.864

.