Correct solutions from Mary of Birchwood High School and Andrei of School 205 Bucharest have contributed to the edited solution below.

As triangle DEF is equilateral, all its angles are 60°.

Angle AEF= 180° – 60° – c° = 120° – c°

Similarly

Angle BFD = 120 - b°
Angle EDC = 120 - a°

From triangle FAE, I calculate angle A:

As triangle ABC is an isosceles Angle ABC = Angle ACB = x°

Therefore 180° - (120° - b° +a° ) = 180° - (120° - a° +c° )
Therfore 60° + b° - a° = 60° + a° - c°
Therefore 2a = b + c
Therefore a = (b + c)/2

Part Two

If a=b=c

Angle ABC = 180° - (120 - b° +a° ) = 180° - (120 - a° +a° ) = 60°
Angle ACB = 180° - (120 - a° +c° ) = 180° - (120 - a° +a° ) = 60°
Therefore angle BAC is 60°

Therefore triangle ABC is equilateral.