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  <id>438</id>
  <path>/www/nrich/html/content/02/10/15plus3/</path>
  <resourceTypeID>1</resourceTypeID>
  <last_published>2011-02-01T00:00:01</last_published>
  <indexXML>&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;p&gt;Show that for natural numbers $x$ and $y$ if ${x\over y}&amp;gt; 1$ then&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
$${x\over y}&amp;gt; {(x+1)\over(y+1)}&amp;gt; 1.$$&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Hence prove that&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
$$P = {2\over 1}{\cdot}{4\over 3}{\cdot}{6\over 5}{\cdots} {k\over k-1}&amp;gt; \sqrt{k+1}.$$&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
This shows that the product $P=\prod_{i=1}^n{2i\over{2i-1}}$ tends to infinity as $n$ tends to infinity. Now, using a similar method, show that&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
$$Q = {2\over 1}{\cdot}{4\over 3}{\cdot}{6\over 5}{\cdots}{100\over 99}&amp;gt; 12.$$&lt;/p&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML/>
  <noteXML/>
  <clueXML>&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
The first part of the question asks you to show that for natural
numbers $x$ and $y$ if ${x\over y}&amp;gt; 1$ then &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
$${x\over y}&amp;gt; {(x+1)\over(y+1)}&amp;gt; 1.$$ &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Here's a hint for this: try starting with $x&amp;gt; y$, which you are
given, and adding $xy$ to both sides of the inequality. &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
For the next part of the question you are given a product $P$ and
the hint to consider $P^2$ and clearly the first part of the
question should come in useful. Look out for a 'magic concertina'
effect!! &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
If you can prove the second inequality then you will have shown
that $P$ gets bigger and bigger without limit as you put more terms
into the product which proves that the product diverges, hence the
title of the question! &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
For the last bit of the question, taking $k=100$ and repeating the
last trick leads to the disappointing conclusion that $Q^2&amp;gt; 
101$, this estimate is not good enough. &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Go back to the drawing board and do some neat estimating of $Q^2$
calculating the product of the first few terms exactly and using
the concertina method on the rest. This will quickly give you the
result. This is a good illustration of what mathematicians do all
the time with inequalities. They go on sharpening them to get
better and better estimates until they get close enough for their
purposes. &lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</clueXML>
  <canonXML/>
  <end_user_role>2</end_user_role>
  <difficulty>3</difficulty>
  <keystage1>0</keystage1>
  <keystage2>0</keystage2>
  <keystage3>0</keystage3>
  <keystage4>0</keystage4>
  <keystage4plus>1</keystage4plus>
  <title>Diverging</title>
  <description>Show that for natural numbers x and y if x/y &amp;gt; 1 then
x/y&amp;gt;(x+1)/(y+1}&amp;gt;1. Hence prove that the product for i=1 to n
of [(2i)/(2i-1)] tends to infinity as n tends to infinity.</description>
  <spec_group>Using, Applying and Reasoning about Mathematics
    <specifier>Mathematical reasoning &amp; proof</specifier>
  </spec_group>
  <spec_group>Algebra
    <specifier>Manipulating algebraic expressions/formulae</specifier>
  </spec_group>
  <spec_group>Algebra
    <specifier>Inequality/inequalities</specifier>
  </spec_group>
</resource>