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  <resource>
  <id>635</id>
  <path>/www/nrich/html/content/99/03/six6/</path>
  <resourceTypeID>1</resourceTypeID>
  <last_published>2011-02-01T00:00:01</last_published>
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&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
A 3 digit number is multiplied by a 2 digit number and the calculation is written out as shown below.&lt;br&gt;&lt;/br&gt;
Each star like this stands for one digit.&lt;br&gt;&lt;/br&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;&lt;mdo:image alt=&quot;&quot; height=&quot;25&quot; src=&quot;star.gif&quot; width=&quot;28&quot;&gt;&lt;/mdo:image&gt;&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;Apart from the zero shown the only digits which occur are 2, 3, 5 and 7. This is sufficient information to complete the whole multiplication.&lt;/div&gt;
&lt;table&gt;
&lt;tbody&gt;
&lt;tr&gt;
&lt;td&gt;&lt;br&gt;&lt;/br&gt;
&lt;div style=&quot;text-align: center;&quot;&gt;&lt;mdo:image alt=&quot;&quot; height=&quot;207&quot; src=&quot;Lmult.gif&quot; width=&quot;244&quot;&gt;&lt;/mdo:image&gt;&lt;/div&gt;
&lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt;&lt;br&gt;&lt;/br&gt;
&lt;div&gt;This is sufficient information to complete the whole multiplication sum.&lt;/div&gt;
&lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt;&lt;br&gt;&lt;/br&gt;
&lt;div&gt;You might find &lt;a href=&quot;/content/99/03/six6/635.pdf&quot;&gt;this sheet&lt;/a&gt; useful for working on the problem,&lt;/div&gt;
&lt;/td&gt;
&lt;td colspan=&quot;4&quot;&gt; &lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt; &lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;/tr&gt;
&lt;/tbody&gt;
&lt;/table&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;p&gt;Catherine, Rachel &amp;amp; Fiona from The Mount School, York, Sonia
from Madras College, and the KS3 Maths Club from Strabane Grammar
School all solved this. Everyone used trial and improvement but
soon realised that there could not be a 2 in the two original
numbers. James of Hethersett High School, Norwich gave the best
explanation of the method. The answer is 775 multiplied by 33.&lt;/p&gt;
 
&lt;table&gt;
&lt;tbody&gt;
&lt;tr&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;7&lt;/td&gt;
&lt;td&gt;7&lt;/td&gt;
&lt;td&gt;5&lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;x&lt;/td&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;3&lt;/td&gt;
&lt;td&gt;3&lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td colspan=&quot;4&quot;&gt;
&lt;hr&gt;&lt;/hr&gt;&lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;2&lt;/td&gt;
&lt;td&gt;3&lt;/td&gt;
&lt;td&gt;2&lt;/td&gt;
&lt;td&gt;5&lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt;2&lt;/td&gt;
&lt;td&gt;3&lt;/td&gt;
&lt;td&gt;2&lt;/td&gt;
&lt;td&gt;5&lt;/td&gt;
&lt;td&gt;0&lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td colspan=&quot;5&quot;&gt;
&lt;hr&gt;&lt;/hr&gt;&lt;/td&gt;
&lt;/tr&gt;
&lt;tr&gt;
&lt;td&gt;2&lt;/td&gt;
&lt;td&gt;5&lt;/td&gt;
&lt;td&gt;5&lt;/td&gt;
&lt;td&gt;7&lt;/td&gt;
&lt;td&gt;5&lt;/td&gt;
&lt;/tr&gt;
&lt;/tbody&gt;
&lt;/table&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</solutionXML>
  <noteXML/>
  <clueXML/>
  <canonXML/>
  <end_user_role>2</end_user_role>
  <difficulty>5</difficulty>
  <keystage1>0</keystage1>
  <keystage2>0</keystage2>
  <keystage3>1</keystage3>
  <keystage4>0</keystage4>
  <keystage4plus>0</keystage4plus>
  <title>Long Multiplication</title>
  <description>A 3 digit number is multiplied by a 2 digit number and the
calculation is written out as shown with a digit in place of each
of the *'s. Complete the whole multiplication sum.</description>
  <spec_group>Decision Mathematics and Combinatorics
    <specifier>Algorithms</specifier>
  </spec_group>
  <spec_group>Calculations and Numerical Methods
    <specifier>Multiplication &amp; division</specifier>
  </spec_group>
  <spec_group>Using, Applying and Reasoning about Mathematics
    <specifier>Trial and improvement</specifier>
  </spec_group>
  <spec_group>Secondary Mapping Document
    <specifier>MD Number operations and calculation methods</specifier>
  </spec_group>
</resource>