Back Fitter
After a while spent as a toughnut, we
recieved the solution to this problem. We were very pleased to see
that one of our younger solvers, Jonathan, realised that the first
graph was $y=0.5 x$. Impressively, a full solution was sent in by
James from Bay House, where all of his functions gave a close fit
with the data -- well done James!
James' suggestions agreed with ours in six
of the cases, but differed in four cases. Perhaps you might like to
consider which you feel are the closer fit?
Experiment 1: $y=x/2$
Experiment 2: $y=\sin(x)
$
Experiment 3: $y=x^2$
Experiment 4:
$y=x-\sin(2x)$
Experiment 5: $y=5\log_{45}(x+1)$ (we got $\sqrt{x}$)
Experiment 6: $y=(\sin(1.7x)+1)/2$ (we got $\sin^2(x)$)
Experiment 7: $y=-0.6+(\log_{10}(6x))^{-1}$ (we got
$\frac{1}{1+x^2}$)
Experiment 8: $y=\log_{15}(7x+1)$ (we got $1.65x/(1+x)$)
Experiment 9:
$y=\cos(2x)$
Experiment 10:
$y=2^x$