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  <id>7138</id>
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  <last_published>2011-02-01T00:00:01</last_published>
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&lt;br&gt;&lt;/br&gt;
&lt;p&gt;The diagram shows a regular 9-sided polygon (a &lt;span style=&quot;font-style: italic;&quot;&gt;nonagon&lt;/span&gt; or an &lt;span style=&quot;font-style: italic;&quot;&gt;enneagon&lt;/span&gt;) with two of the sides extended to meet at the point &lt;span style=&quot;font-style: italic;&quot;&gt;X&lt;/span&gt;.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
What is the size of the acute angle at &lt;span style=&quot;font-style: italic;&quot;&gt;X&lt;/span&gt;?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;mdo:image alt=&quot;&quot; height=&quot;175&quot; src=&quot;44%202010.png&quot; width=&quot;273&quot;&gt;&lt;/mdo:image&gt;&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
If you liked this problem, &lt;a href=&quot;http://nrich.maths.org/4856&amp;amp;part=&quot;&gt;here is an NRICH task&lt;/a&gt; which challenges you to use similar mathematical ideas.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
 &lt;/p&gt;

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&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p style=&quot;text-align: center;&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;mdo:image alt=&quot;&quot; height=&quot;175&quot; src=&quot;44%202010.png&quot; style=&quot;text-align: center;&quot; width=&quot;273&quot;&gt;&lt;/mdo:image&gt;&lt;/p&gt;
&lt;p&gt;&lt;br&gt;&lt;/br&gt;
The exterior angles of a regular nonagon are $360^{\circ}\div 9 = 40^{\circ}$, whence the interior angles are $180^{\circ} - 40^{\circ}= 140 ^{\circ}$.&lt;br&gt;&lt;/br&gt;
 &lt;br&gt;&lt;/br&gt;
In the arrowhead quadrilateral whose rightmost vertex is &lt;span style=&quot;font-style: italic;&quot;&gt;X&lt;/span&gt;, three of the angles are $40^{\circ}$, $40^{\circ}$ and $360^{\circ} - 140^{\circ}=220^{\circ}$ and these add up to $300^{\circ}$.&lt;br&gt;&lt;/br&gt;
 &lt;br&gt;&lt;/br&gt;
So the agle at &lt;span style=&quot;font-style: italic;&quot;&gt;X&lt;/span&gt; is $60^{\circ}$.&lt;br&gt;&lt;/br&gt;
 &lt;br&gt;&lt;/br&gt;
[It is now posible to see that the entire nonagon can fit neatly inside an equilateral triangle and so the angle &lt;span style=&quot;font-style: italic;&quot;&gt;X&lt;/span&gt; $60^{\circ}$ ]&lt;br&gt;&lt;/br&gt;
 &lt;br&gt;&lt;/br&gt;
 &lt;mdo:image alt=&quot;&quot; height=&quot;263&quot; src=&quot;44%202010%20b.PNG&quot; width=&quot;291&quot;&gt;&lt;/mdo:image&gt;&lt;/p&gt;&lt;/mdoxml&gt;</solutionXML>
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  <clueXML/>
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  <end_user_role>2</end_user_role>
  <difficulty>3</difficulty>
  <keystage1>0</keystage1>
  <keystage2>0</keystage2>
  <keystage3>1</keystage3>
  <keystage4>0</keystage4>
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  <title>Weekly Problem 44 - 2010</title>
  <description>Weekly Problem 44 - 2010</description>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Angle properties of shapes</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Angles</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Other polygons</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Quadrilaterals</specifier>
  </spec_group>
  <spec_group>Secondary Mapping Document
    <specifier>Angles and polygons</specifier>
  </spec_group>
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