Problem
Solution
Weekly Problem 6 - 2011
By comparing
b
and
c
first, we have $b= 8^8= (2^3)^8=2^{24}=(2^2)^{12}=4^{12}> 3^{11} = c$
so $c< b$.
But also $b= 2^{24}< 2^{25}=a$ so $b< a$.
Together these give $c< b< a$.