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&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p&gt;Choose any number. This is going to be your particular number for this proof.&lt;br&gt;&lt;/br&gt;
Square your chosen number.&lt;br&gt;&lt;/br&gt;
Subtract your starting number.&lt;br&gt;&lt;/br&gt;
Is the number you&amp;#39;re left with odd or even?&lt;br&gt;&lt;/br&gt;
Create a model or a picture of your calculation, using your chosen number, and examine this model carefully.&lt;br&gt;&lt;/br&gt;
Can you use this one model to prove that your result is always true and not just true for the particular number that you chose to start with?&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;
&lt;p&gt; &lt;/p&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p&gt; &lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;Nearly $80$ solutions were sent in! These had many examples that had even answers. We did suggest that you went a bit further and here we have some ideas.&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;First from&lt;/span&gt; &lt;span class=&quot;editorial&quot;&gt;Owen  from the Montessori School of Wooster, Ohio , USA &lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;br&gt;&lt;/br&gt;
A square number subtracted by its self (X squared - X) always has to be even. It will always be a even number because an even number times a odd number ($3 x 3 = 3 x 2$ ) is always even&lt;/p&gt;
&lt;p&gt;(ex. $4 x 4 - 4 = 4 x 3 = 12, 5 x 5 - 5 = 4 x 5 = 20$)&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;Amy  from Claremont Primary  School in the UK   had the following thoughts;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;$2 x 2 = 4$&lt;br&gt;&lt;/br&gt;
$4 - 2 = 2$ (even)&lt;br&gt;&lt;/br&gt;
Answer is even with an even number starting point&lt;/p&gt;
&lt;p&gt;$3 x 3 = 9$&lt;br&gt;&lt;/br&gt;
$9 - 3 = 6$ (even)&lt;br&gt;&lt;/br&gt;
Answer is even with an odd number starting point&lt;/p&gt;
&lt;p&gt;Therefore answer is always even. Why?&lt;/p&gt;
&lt;p&gt;The answer will always be even because an odd number squared makes another odd number. An even number squared makes an even number. And an even number take away another even number makes another even number. But quite strangely an odd number take away another odd number also makes an even number.&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;From Jasmine, Arran, Rebecca and Thomas  at St. Mary&amp;#39;s School Shawbury  in England , we had a similar thought;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;br&gt;&lt;/br&gt;
The answer is even. We know this because, when you square an even number you always get an even number, but when you take an even number away from the number that you now have, you still remain an even number, no matter what number you started with.&lt;br&gt;&lt;/br&gt;
When you square an odd number, it should result as another odd number, but when you subtract an odd number, from the number you have now, it will result as an even number.&lt;br&gt;&lt;/br&gt;
e.g.  Even squared = even - even = even.&lt;br&gt;&lt;/br&gt;
e.g.  Odd squared = odd - odd = even.&lt;/p&gt;
&lt;p&gt;We tried this with $1,2,  3$ digit numbers and they all ended even, we also tried different odd and even numbers and found the same result, all the answers were even.&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;Olly  from Bourton Meadow Academy  in England , wrote;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;br&gt;&lt;/br&gt;
It is always even because the multiples of an even number are even&lt;br&gt;&lt;/br&gt;
$(2a)(2a+1) = 6a$&lt;br&gt;&lt;/br&gt;
If you use an odd number it is simply this formula backwards&lt;br&gt;&lt;/br&gt;
$(2a+1)(2a) = 6a$&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;Finally Victor and Elliott  from  Kenakena School  in New Zealand ;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;$X² - X =$ even. If $X$ is odd. $X²$ is odd. so $X² - X = $ even.&lt;br&gt;&lt;/br&gt;
If $X$ is even. $X²$ is even. so $X² - X = $even.&lt;/p&gt;
&lt;p&gt;Side proof : how even - even = even and odd - odd = even:&lt;/p&gt;
&lt;p&gt;If n and e is an arbitrary whole number, then even = $2n$, so even - even $= 2n - 2e = 2(n - e)$. Thereby, even - even = even.&lt;/p&gt;
&lt;p&gt;So odd$ = 2n + 1$. So odd - odd = $2n + 1 - (2e + 1) = 2n - 2e + 1 - 1 = 2(n- e)$.&lt;br&gt;&lt;/br&gt;
Thereby, odd minus odd = even.&lt;br&gt;&lt;/br&gt;
 &lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;We had a few very late in the month suggestions from&lt;/span&gt; &lt;span class=&quot;editorial&quot;&gt;Jack, Daniel, Sophiie, Isobel and Ryan at&lt;/span&gt; &lt;span class=&quot;editorial&quot;&gt;Keidmarch Primary School&lt;/span&gt;&lt;br&gt;&lt;/br&gt;
 &lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;Thank you all for your hard work and the emails.&lt;/span&gt;&lt;/p&gt;&lt;/mdoxml&gt;</solutionXML>
  <noteXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;Why do this problem?&lt;/h3&gt;
&lt;p&gt;This problem captures the essence of generic proof. This is a tricky concept to grasp but it draws attention to mathematical structures that are not often addressed at primary school level. It is possible that only very few children in the class may grasp the idea but this is still a worthwhile activity which provides opportunities for children to explore odd and even numbers and the
relationship between them. Generic proof involves examining one example in detail to identify structures that will prove the general result. Proof is a fundamental idea in mathematics and in encouraging them to do this problem you will be helping them to behave like mathematicians.&lt;/p&gt;
&lt;p&gt;The article entitled &lt;a href=&quot;http://nrich.maths.org/8081&quot;&gt;Take One Example&lt;/a&gt; will help you understand how this problem supports the development of the idea of generic proof with the children. Reading it will help you to see what is involved.&lt;/p&gt;
&lt;p&gt;This problem builds on the ideas explored in &lt;a href=&quot;http://nrich.maths.org/8059&quot;&gt;Two Numbers Under the Microscope&lt;/a&gt;, &lt;a href=&quot;http://nrich.maths.org/8063&quot;&gt;Take Three Numbers&lt;/a&gt; and &lt;a href=&quot;http://nrich.maths.org/8062&quot;&gt;Odd Times Even&lt;/a&gt;. You may find it helpful to tackle these before this one as we offer less support in the posing of the question in this case.&lt;/p&gt;
&lt;h3&gt;Possible approach&lt;/h3&gt;
&lt;p&gt;Introduce the idea using numbers that the children are comfortable to work with and can represent easily either on paper or using apparatus such as Multilink cubes, counters or Dienes blocks. It will be helpful to use apparatus or drawings that support a model of multiplication based on arrays. The children might all be working with different numbers but should all arrive at the same
conclusion. This result is the focus of the generic proof. The task is to examine the example for features that will be true in every case and so establish an argument to support their conjecture. This argument is the generic proof.&lt;/p&gt;
&lt;p&gt;A different approach to proving the same result can be found in the problem &lt;a href=&quot;http://nrich.maths.org/2280&quot;&gt;Odd Squares&lt;/a&gt;.&lt;/p&gt;
&lt;h3&gt;Key questions&lt;/h3&gt;
&lt;p&gt;How would you like to represent these numbers?&lt;/p&gt;
&lt;p&gt;Is the number you&amp;#39;re left with odd or even?&lt;/p&gt;
&lt;p&gt;Can you see anything in your example that would work in exactly the same way if you used a different starting number?&lt;/p&gt;
&lt;p&gt;Can you say what will happen every time you choose a number, square it and subtract the number you chose?&lt;/p&gt;
&lt;p&gt;Can you convince your friend that this is true?&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;
&lt;h3&gt;Possible extension&lt;/h3&gt;
&lt;p&gt;Look at the relationship between successive square numbers. For example, what is the difference between 5 squared and 6 squared? Can you find a general rule? Can you prove it by looking at the structure of a specific case?&lt;/p&gt;
&lt;h3&gt;Possible support&lt;/h3&gt;
&lt;p&gt;It may be helpful for children who are struggling to look at &lt;a href=&quot;http://nrich.maths.org/8062&quot;&gt;Odd times even&lt;/a&gt;. Rehearsing the nature of generic proof may also be helpful and the article Take one example may help  you do do this with the children. &lt;/p&gt;
&lt;p&gt;&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
 &lt;/p&gt;&lt;/mdoxml&gt;</noteXML>
  <clueXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p&gt;How about using a pattern of dots to show your square number?&lt;/p&gt;&lt;/mdoxml&gt;</clueXML>
  <canonXML/>
  <end_user_role>2</end_user_role>
  <difficulty>5</difficulty>
  <keystage1>0</keystage1>
  <keystage2>1</keystage2>
  <keystage3>0</keystage3>
  <keystage4>0</keystage4>
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  <title>Square subtraction</title>
  <description>Look at what happens when you take a number, square it and subtract your answer. What kind of number do you get? Can you prove it?</description>
  <spec_group>Using, Applying and Reasoning about Mathematics
    <specifier>Mathematical reasoning &amp; proof</specifier>
  </spec_group>
  <spec_group>Using, Applying and Reasoning about Mathematics
    <specifier>Making and proving conjectures</specifier>
  </spec_group>
  <spec_group>Numbers and the Number System
    <specifier>Odd and even numbers</specifier>
  </spec_group>
  <spec_group>Calculations and Numerical Methods
    <specifier>Multiplication &amp; division</specifier>
  </spec_group>
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