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  <id>9766</id>
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  <last_published>2013-01-04T16:13:48</last_published>
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&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
 &lt;mdo:image src=&quot;weekly.png&quot; style=&quot;float: left;&quot;&gt;&lt;/mdo:image&gt;What is the value of $x$ in this diagram?&lt;/mdoxml&gt;</indexXML>
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&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;mdo:image src=&quot;weeklysol.png&quot; style=&quot;float: right;&quot;&gt;&lt;/mdo:image&gt;&lt;br&gt;&lt;/br&gt;
Alternate angles BDF and DFG are equal, so lines BD and FG are parallel.&lt;br&gt;&lt;/br&gt;
Therefore angle BCA = angle FGC = $80^{\circ}$ (corresponding angles).&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Consider triangle ABC: $x + 70 + 80 = 180$ so $x=30$.&lt;/mdoxml&gt;</solutionXML>
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  <title>Weekly Problem 7 - 2013</title>
  <description>Weekly Problem 7 - 2013</description>
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